Hi to all,
This is all Information I myself have gathered from the MECP Installers Guide book.

Alright Here's the Question!

I am trying to figure out how much pull on my alternator I am getting from the amp.

Here is the formula We use to figure this out

I = (Po - n*Po + Po) / V

Now

I = amperes
Po=RMS
n=efficiency
V=voltage

So for me its:

I = (3000 - .8*3000 + 3000) / 13.8

So I do this

3000*.8 and i get 2400

3000-2400=600

600+3000

3600/13.8

260.87 This is my amperage draw correct?


and if I'm correct for everyone else heres an easier equation for this:

I = (2-n)Po/V

So for me this would go

1. 2-.8 =1.2
2. 1.2*3000=3600
3. 3600/13.8

And there we go. 260.87!!!!!

Now, We must remember that Most Class D Amplifiers have a 80% Efficiency Rating and Most Class A/B Amplifiers have a 60-70% efficiency Rating!

3000rms thats a lot of power for sound system, what are you doing to increase the amps out of your car to power this system?

You would need like 3-4 Batteries too keep up with that power. What kind of system are you running?

he would need a 2-3 alternators, batteries are a waste of money if you cant charge them

He's in the UK so that would be a metric 3000rms.

Not sure how to convert to 'merican.

An ambulance alternator is what people here use for hardcore sound systems.